74HC76 DATASHEET PDF

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Sign up using Facebook. JK1 and JK2 need to initialize in opposite states, don’t they?

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I’ve a button that sets the starting 1 in the first jk, so I think that the problem isn’t about Preset or Clear pin. I’m using 74HC76 integrated that contains two jk.

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Sign up or log in Sign up using Google. I’m building a simple ring counter with two jk flip-flop. I initialize the first jk with 1 using a button and preset and clear pin.

74HC76 Datasheet Renesas pdf data sheet FREE from

Email Required, but never shown. This is my schematic very basic: Do not, ever, disconnect the VCC pin when debugging, because that breaks chips. For the Preset pin where you have a switch to pull it to ground, you must also have a resistor 5K – 10K to Vcc to ensure the preset pin is high when the switch is not taking it low.

Without a resistor in series with each LED is is likely that the corresponding Q output is being dragged down to a voltage that is not high enough to be recognized as a legitimate high level by the following J input.

If no what’s the matter of my circuit? About Preset and Clear pin I’m managing them well: By using our site, you acknowledge that you have read and understand our Cookie PolicyPrivacy Policyand our Terms of Service.

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On CMOS parts, all unused inputs must be connected, directly or through a resistor, to either Vcc or ground, whichever is required to make the part work as required. Post as a guest Datashwet.

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How do you ensure this? This is the integrated pinout: Thanks for your advice. The problem is that in the circuit that I’m observing on my desk the ring counter only works when pin 5 Vcc is unwired.

Sign up using Email and Password. Home Questions Tags Users Unanswered. It means that if I wire pin 5 to Vcc I got always 10 output.